X^2+14x+48=160

Solution for X^2+14x+48=160 equation:

X^2+14X+48=160

We move all terms to the left:

X^2+14X+48-(160)=0

We add all the numbers together, and all the variables

X^2+14X-112=0

a = 1; b = 14; c = -112;
Δ = b2-4ac
Δ = 142-4·1·(-112)
Δ = 644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{644}=\sqrt{4*161}=\sqrt{4}*\sqrt{161}=2\sqrt{161}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{161}}{2*1}=\frac{-14-2\sqrt{161}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{161}}{2*1}=\frac{-14+2\sqrt{161}}{2}
$